BCH210H1 Lecture Notes - Lecture 24: Maltotriose, Ketose, Organic Compound
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BCH210H1 Full Course Notes
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Below are shown two simple sugars as talked about last. Recall that alpha means the oh is pointing down at c1. Recall anomeric carbon was a hemiacetal --> you will form a full acetal structure. Recall that the cyclic formation was intramolecular reaction. Similar nucleophilic attack from an oh that attacks the anomeric carbon. This is a condensation reaction that creates a bond. This creates the functional group: glycosidic bond --> this is a full acetal structure. Condensation because a water is removed --> a water is made. O(cid:374)(cid:272)e you ha(cid:448)e a gly(cid:272)osidi(cid:272) li(cid:374)kage, you do(cid:374)"t (cid:374)a(cid:373)e it like (cid:271)efore (cid:374)o(cid:449) Sugar on the left is no longer a reducing sugar because of this linkage. Recall that this is because you need more than one step to break it at anomeric. However, sugar at the right is a reducing sugar because anomeric carbon is still free and can still cause an intra-attack to break the ring structure.
