MAT136H1 Lecture Notes - Antiderivative
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MAT136H1 Full Course Notes
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Question #4 (medium): working with acceleration, velocity, displacement, and distance. Displacement is the net distance travelled, so ( ) But distance is the total distance travelled, so | ( )| The given acceleration (in ) and the initial velocity (in ) describe a particle moving along a line: find the velocity at time , find the total distance travelled during the given time interval. Solution: velocity is the anti-derivative of acceleration: So the velocity function at time is: ( ) : note that the distance is not the net but total distance travelled: Factoring ( ) ( )( ), the -intercepts are. + and [ ]; and ( ) over the interval * Taking the anti-derivative, then plugging in endpoints of each subinterval:
