SPH PH 510 Lecture 15: SPH PH510 LECTURE 15
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6 Aug 2019
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C13 NMR spectrum
I cannot get this right.. Please help..
given shifts of C4H6O
C13 NMR shifts | Dept 90 | Dept 135 |
194.7 | + | + |
146.0 | o | o |
134.4 | o | - |
14.0 | o | + |
I found DU or RDB=2.
194.7 could be C=O, 134.4 (CH2 for it exhibits a - on DEPT 135 o on DEPT90. 14.0=CH3
Please help with the correct structure.
Thank you.