ENVS 2000 Lecture 1: recitation

Given the acceleration vector A(t) = t2 i - 2 j + e3t k, and the initial position R(0) = 2i+j - k and velocity V(0)= i - j - 2 k, find (A) the velocity and (B) the position vector at time t. V(t) = i + j + k R(t) = i + j + k

Given that the acceleration vector is a (t) = (-4 cos(-2t)) i + (-4 sin (-2t)) j + (-4t)k, the initial velocity is v (0) = i + k, and the initial position vector is r (0) = i + j + k, compute: The velocity vector v (t) = i+ j+ k The position vector r (t) = i+ j+ k

(1 point) Find the position vector R(t) given the velocity V(t) = (21+ 4) i + 4 sin(40j + 5t4k and the initial position vector R(0) =-2i +j +2k. R() =