DAA 2105 Lecture Notes - Lecture 5: Confidence Interval, Test Statistic
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From (a) and (b) in this example we get different values of test statistic, d. f. and p- value but we conclude same result of these both test. please give me thumb up. > #a)by using two sample t- test > to test ho: mul=mu2 vs h1: mul not egqual to mu2 group1-c (48. 86, 50. 60,51. 02,47. 99,54. 20,50. 51. 13) groupl (1) 48. 86 50. 60 51. 02 47. 99 54. 20 50. 66 45. 91 48. 79 47. 76 51. 13 group2-c (48. 88,52. 63, 52. 55, 50. 94,53. 02,50. 66, 47. 78, 48. 44, 48. 92, 1. 148485 bample estimates: mean cf x mean ofy 49. 692 50. 545 p alpha=0. 05 > =decigion rule: if p-value >0. 05 (alpha), hence we accept ho, at 54 1. o. 3. =18, and p-value=0. 3824 ecnclusion:we conclude that there 13 no change in their means. > tb) by using paired t-test > to test ho: mud-0 v/s mud not equals to 0 > group1-c (48. 86,50. 60, 51. 02,47. 99, 54. 20, 50. 66, 45. 91, 48. 79, 47. 76, 51. 13) Group1 [1] 48. 86 50. 60 51. 02 47. 99 54. 20 50. 66 45. 91 48. 79 47. 76 51. 13 > group2-c(48. 88,52. 63,52. 55,50. 94,53. 02,50. 66,47. 78,48. 44, 48. 92,51. 63):