BAD 200 Lecture 6: HIST MISC_3yt3UiXRmuai

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"we have sigma a_k = sigma^infinity_k = 11/k(k + 2) = sigma^infinity_k = 11/(k^2 + 2k) using test, let sigma b_k = sigma^infinity_k = 1. 1/k^2 since sigma^infinity_k = 11/k(k + 2) lessthanorequalto sigma^infinity_k 1/k^2 , so sigma a_k and sigma b_k both convergent or both also. Note that sigma b_k = sigma^infinity_k 1/k^2 is by p-series thus sigma a_k = sigma^infinity 1/k(k + 2) is also convergent. Further, s = sigma^infinity_k 1/k(k + 2) = 1/2 sigma^infinity_k [1/k - 1/k + 2] s = 1/2[(1/2 + 1/2 + 1/3 + 1/4 + ) - (1/3 + 1/4 + 1/5 + )] = 1/2[(1 + 1/2 +

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