MTH 114 Lecture Notes - Lecture 74: Standard Deviation, Sample Space, Disjoint Sets

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= 5 4 3 2 1; 12! = 12 11 10 9 8 7 6 5 4 3 . = 8 7 6 combination (without repetition) n/[total number of objects] objects taken r/[size of group] at a time (the order doesn"t matter, ex. groups) formula: n! (n-r)! (note: after cancelling out almost everything you are left with: the first r factors of n! (without repetition) n/[total number of objects] objects taken r[size of group] at a time (the order does matter/make a difference, ex. lists) formula: n! (n-r)! (note: (n-r)! cancels out part of n!, ex. = 6 5 = 30 & 12!/9! 4/52 - 1/52 [which is the ace of spades]) Probability of a or b (not both): p(a) + p(b) - 2 p(a /and b) Finding the probability of an empirical event: # of times e/specific outcome occurs. Total # of observed situations in which e could occur.

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