CHE 106 Lecture Notes - Lecture 8: Total Synthesis, Chemical Equation, Ammonia

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22 Jan 2018
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CHE 106 Full Course Notes
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9/26/17: stoichiometry the calculation of the quantities of reactants and products involved in a chemical reaction. Convert mass to moles: mole = g/mw mole = 110g/17 g/mol = 6. 5 mol nh3, 2. Find moles of n2 and h2 needed for reaction: n2 6. 5 mol nh3/1 x 1 mol n2/2 mol nh3 = 3. 3 mol n2, h2 6. 5 mol nh3/1 x 3 mol h2/2 mol nh3 = 9. 8 mol h2, 3. Find the number of moles mno2 (mw = 86. 9 g/mol: mole = 25 g/86. 9 g/mol = 0. 288 mol mno2, 2. Then convert to oles of what is desired (mol hcl: 0. 288 mol mno2/1 x 4 mol hcl/1 mol mno2 = 1. 15 mol hcl, 3. If 0. 60 mol zn is added to hydrochloric acid containing 1. 04 mol hcl, how many moles of h2 are produced: need to find limiting reagent, 1. (cid:3032)(cid:3032)(cid:3047)(cid:3030) (cid:3032)(cid:3031) x 100: should never be more than 100%, example percent yield calculation:

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