PHYSICS 5C Lecture Notes - Lecture 7: Farad, Resistor, Electric Field

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orangemole240

6 Nov 2018

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Concepts " electric charges and forces similar to batteries ) electric field electric potential and potential energy capacitors . Store charge and electric energy charge can be released quickly since no chemical reactions are involved. Capacitors just need to be two conductors separated by an isolator ( air ) Capacitors can thus drive applications that require a lot of charge flowing in a short time flash laser. C when you close the switch you are discharging the voltage. Measure how much charge a capacitor can store for a given voltage. Pf - pet e does not depend on. V but only on the shape / material ( q and. C = e : for parallel plate cap . V : d =a . d c = Ai d can store you more charge by making the plate bigger. This is different from the kinetic energy that a particle acquires after passing through the potential between the two plates.

Related Questions

You have two identical capacitors and an external potential source. (a) Compare the total energy stored in the capacitors when they are connected to the applied potential in series and in parallel. (b) Compare the maximum amount of charge stored in each case. (c) Energy storage in a capacitor can be limited by the maximum electric field between the plates. What is the ratio of the electric field for the series and parallel combinations?

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To understand the meaning of capacitance and ways of calculating capacitance.

When a positive charge q is placed on a conductor that is insulated from ground, an electric field emanates from the conductor to ground, and the conductor will have a nonzero potential V relative to ground. If more charge is placed on the conductor, this voltage will increase proportionately. The ratio of charge to voltage is called the capacitance C of this conductor: C=q/V.

Capacitance is one of the central concepts in electrostatics, and specially constructed devices called capacitors are essential elements of electronic circuits. In a capacitor, a second conducting surface is placed near the first (they are often called electrodes), and the relevant voltage is the voltage between these two electrodes.

This tutorial is designed to help you understand capacitance by assisting you in calculating the capacitance of a parallel-plate capacitor, which consists of two plates each of area A separated by a small distanced with air or vacuum in between. In figuring out the capacitance of this configuration of conductors, it is important to keep in mind that the voltage difference is the line integral of the electric field between the plates.

Assume that charge -q is placed on the top plate, and +q is placed on the bottom plate. What is the magnitude of the electric field E between the plates?
What is the voltage V between the plates of the capacitor?

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PHYSICS 5C Lecture Notes - Lecture 7: Farad, Resistor, Electric Field

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