MA 35100 Lecture Notes - Lecture 10: Solution Set, If And Only If
Document Summary
But they are in fact equal (cid:8869) see handout. So [ a 1 b] %f [ i e ] crref) [ a 10] [ i 0 ] If we solve ax = b by ge , get translation vector t and spanning vectors , then nullspace (a) we can just read off (span of the spanning vectors) . When we have any vector of constants c , if ax = c is consistent , then the general solution given by ge to d- = c is of the form : I + t , , i . + tie k , where , Are spanning vectors found when solving any consistent ax = b and f is a particular solution to ax = c ( i. e. at = c) . In particular , if ax = b has infinitely many solutions : Ax = c cif consistent) also has infinitely many solutions.
