MA 35100 Lecture Notes - Lecture 21: Parallelogram
Document Summary
For a matrix transforth given by man a, the image of ta is. & b+ rw; there is x 24" with ta (x)= b3. : sberw:ax: b has a solution 301 (a) ex: To understand what happens to subsets of domain under a matrix transforth, we have: Prop 3. 1: a man, ta (x):ax; in sends line segments to line segments or points e saye= ex++(8-x): ++(0,173. E = i so ta (x++ (8-x)) = a (x ++ (2-x))=ax + + (ay-ax) (cid:8869) segment from ax- ay unless ax: ay: see handout. Stransformations: dilation, rotation, projection, reflection, identity, shear. Ex : find a matrix transfmtn that transforms the parallelogram. [ 9 ] [ {] into pz : [ - } ] [ 8 ] [ % ] [ { ] " choose which corners correspond: 0 = 0 for any a.
