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salmonox574Lv1
6 Nov 2019
Let V be a vector space of dimension n > k. Let. S = {upsilon_1 upsilon_k} be a linearly independent set. Then there exists a basis such that the first k basis vectors are upsilon_1, upsilon_k. Show transcribed image text Let V be a vector space of dimension n > k. Let. S = {upsilon_1 upsilon_k} be a linearly independent set. Then there exists a basis such that the first k basis vectors are upsilon_1, upsilon_k.
Let V be a vector space of dimension n > k. Let. S = {upsilon_1 upsilon_k} be a linearly independent set. Then there exists a basis such that the first k basis vectors are upsilon_1, upsilon_k.
Show transcribed image text Let V be a vector space of dimension n > k. Let. S = {upsilon_1 upsilon_k} be a linearly independent set. Then there exists a basis such that the first k basis vectors are upsilon_1, upsilon_k.1
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Jean KeelingLv2
20 Jul 2019