Log in
Algebra
1
answer
0
watching
119
views
12 Nov 2019

Solve for X & Y using the two below equations. How can I go about doing this? I know the answers from my text book but I am unsure of what steps it takes to get there. Thank you!

x/y=1.585

x+y=0.1

Watch
1
answer
0
watching
119
views

For unlimited access to Homework Help, a Homework+ subscription is required.

Tod Thiel
Tod ThielLv2
12 Nov 2019

Unlock all answers

Get 1 free homework help answer.
Already have an account? Log in
Share

Related questions

Hello there. I just had one question dealing with binary operationsin abstract algebra. I need to see if this operation has anidentity element for all x in R. The operation is as follows:x*y=|x-y| This is what I did. I basically broke it up since thereis an absolute value. x*e=|x-e| = x-e if x> 0 or -(x-e) if xe,then x*e= x-e. We need to find e for x*e=x. So x-e=x and e=0. Nowmy first question is this: 1) If x>0, then why for thisequation, x-e=x, can x be values that are less than 0. It seemslike a contradiction to me. Is e=0 only valid for x>0? Thenafter that I tried out x*0= |x|= x if x>0 and -x if x<0.However, is it just a coincidence that it is x if x>0 and alsowe chose x*0 to be x-0 for x>0? I mean, it seems like either way( whether you use the |x| way or the (x-e) way, you get x as ananswer). My next question is that if we choose x<0 for the abovex*0=..., then doesn't e change? I am confused about this. I mean inone case we have |x|= -x if x<0, but if x<0, then e changes,doesn't it? Please just help me answer these questions and guide mestep by step through this problem. Thank you.

First off am I correct to say that we are in R^2. The set spans a plane. I know that <1,2> and <2,4> run on the same line, but <5,1> allows us to move through the plane? Letter c and d I don't understand what I am supposed to be putting.

C. would it be <x,y> = C<1,2> we know that it's in the span? or <x,y> = 2 <1,2>

D. I don't know where there wouldn't be a vector on the plane?

Thank you for your help

I can firgure out everything but how do you figure out if this is a vertical or horizontal stretch or shrink? I am getting confused.

Weekly leaderboard

Home
Homework Help 3,900,000
Algebra 190,000
Start filling in the gaps now
Log in