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In pea plants, the appearance of flowers along the main stem isa dominant phenotype called "axial" and is controlled by an alleleT. The recessive phenotype, produced by an allele t, hasflowers only at the end of the stem and is called "terminal."

Pod form displays a dominant phenotype "inflated," controlled byan allele C, and a recessive "constricted" form, producedby the c allele.

A cross is made between a pure-breeding axial, constricted plantand a plant that is pure-breeding terminal, inflated.

Part A

The F1 progeny of this cross are allowed to self-fertilize. Whatis the expected phenotypic distribution among the F2 progeny?

*The answer for this one is 9:3:3:1. I understand this part.

Part B

Suppose that all of the F2 progeny with terminal flowers, i.e.,plants with terminal flowers and inflated pods and plants withterminal flowers and constricted pods, are saved and allowed toself-fertilize to produce a partial F3 generation. What is theexpected phenotypic distribution among these F3 plants?

(Remember to take into consideration the frequency of eachgenotype in the F2 as well as the probability of specific offspringthat result from self-fertilizing each F2 genotype.)

*I don't understand this part. It wants wants an answer in termsof "terminal inflated : terminal constricted."

Part C

If an F1 plant from the initial cross described above is crossedwith a plant that is terminal, constricted, what is the expecteddistribution among the resulting progeny?

*I understand this part. The answer is axial inflated : axialconstricted : terminal inflated : terminal constricted =1:1:1:1

Part D

If the plants with terminal flowers produced by the cross inPart C are saved and allowed to self-fertilize, what is theexpected phenotypic distribution among the progeny?

*I also don't understand this part. They want an answer in termsof "terminal inflated : terminal constricted."

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Hubert Koch
Hubert KochLv2
30 Sep 2019

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