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Two brown-eyedparents are each heterozygous for a recessive blue-eye gene. Whatis the probability that the first two children will beblue-eyed?

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Sixta Kovacek
Sixta KovacekLv2
28 Sep 2019
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Related questions

Information for Questions 1-4. In humans, the brown eye alleleis dominant to the blue eye allele of one of the eye color genes. Ablue-eyed parent and a heterozygous brown-eyed parent would like tohave children together. Use probability calculations to calculatethe probability of the following outcomes. Answer choices on thequiz will be in fraction form (1/4 for example).

1. What is the probability that ALL of their first 3 childrenwill all have blue eyes?

2. What is the probability that NONE of their first 3 childrenwill have blue eyes?

3. What is the probability that EXACTLY 2 of their first 3children will have brown eyes?

4. What is the probability that EXACTLY 2 of their first 3children will have brown eyes OR EXACTLY 2 of their first 3children will have blue eyes?

1. In humans, right-handedness (R) is dominant to left-handedness (r), and brown eyes (B) are usually dominant to blues eyes (b).

a) What are the genotypes of gametes produced by a person heterozygous for both traits?

b) What are the genotypes of gametes for a person heterozygous for brown eyes, but homozygous recessive for left-handedness?

c) Set up a Punnett square for a couple that is heterozygous for both traits. What is the probability that if their first child is brown-eyed and left-handed that the second child is blue-eyed and left-handed?

d) A right-handed, blue-eyed woman marries a right-handed, brown-eyed man. They have two children, one left-handed and brown-eyed and the other right-handed and blue-eyed. By a later marriage with another man, who is also right-handed and brown-eyed, she has seven more children, all of whom are right-handed and brown-eyed. What are the genotypes of the woman and her two husbands?

In humans, the allele for brown eye color (B) is dominant toblue eye color (b). If two heterozygous parents produce children,what are the following probabilities?

A) the first two children have blue eyes

B) A total of 4 children two with blue eyes and the other twowith brown eyes.

C) The first child has blue eyes, and the next two have browneyes

I believe the answer is C due to the ratio of 1 (homologousdominant brown): 2 (heterozygous brown): 1 (homologous bluerecessive). I'm not sure

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