answer

watching

views

17 Jun 2018

In an erythrocyte undergoing glycolysis, what would be the effect of a sudden increase in the concentration of...

a. ATP?

b. AMP?

c. fructose-1,6-bisphosphate?

d. fructose-2,6-bisphosphate?

e. citrate?

f. flucose-6-phosphate?

answer

watching

852

views

For unlimited access to Homework Help, a Homework+ subscription is required.

You have 0 free answers left.
Get unlimited access to 3.8 million step-by-step answers.

Get unlimited access

Already have an account? Log in

Jean KeelingLv2

19 Jun 2018

Unlock all answers

Get 1 free homework help answer.

Already have an account? Log in

Related questions

In liver cells, fructose-2,6-bisphosphate (F-2,6-bP):

a) is an intermediate in both glycolysis and gluconeogenesis.

b)is an intermediate in gluconeogenesis.

c) is an intermediate in glycolysis.

d)is a potent allosteric activator of fructose bisphosphatase and an inhibitor of phosphofructokinase.

e)is a potent allosteric activator of phosphofructokinase and an inhibitor of fructose bisphosphatase.

copperbutterfly212

Problem 9
A mutation in Phosphofructokinase causes the loss of the allosteric site for ATP. Which effect on glycolysis is expected? Explain in detail.
Explain which of the following mutations would result in the opposite effect on the rate of
glycolysis in liver:

a) a mutation causing the loss of the binding site for citrate in phosphofructokinase
b) a mutation causing the loss of the binding site for fructose 1,6-bisphosphate in pyruvate
kinase.
c) A mutation decreasing the activity of adenylate kinase

ultramarinelizard507

Question text

Phophofructokinase-1 (PFK-1) isan allosteric enzyme. Its activity is inhibited by:

Question 18

Notyet answered

Markedout of 1.00

Flagquestion

Question text

When the AMP levelin the cell is ___________ (High/Low), it binds at an allostericsite on the glycolytic enzyme phosphofructokinase and __________(activates/inhibits) it.

Question 19

Notyet answered

Markedout of 1.00

Flagquestion

Question text

In glycolysis, fructose 1,6-bisphosphate is converted to twoproducts with a standard free-energy change (?Go') of +23.8 kJ/mol.Under what conditions (encountered in a normal cell) will thefree-energy change (?G') be negative, enabling the reaction toproceed to the right?

Select one:

a. If the concentrations ofthe two products are high relative to that of fructose1,6-bisphosphate.

b. The reaction will not goto the right spontaneously under any conditions because the G ispositive.

c. Under standard conditions,enough energy is released to drive the reaction to the right.

d. When there is a highconcentration of fructose 1,6-bisphosphate relative to theconcentration of products.

e. When there is a highconcentration of products relative to the concentration of fructose1,6-bisphosphate.