There is a population of 135 deer. Some of the deer in the population are albino which is a rare genetically inherited trait that is only expressed in the phenotype of the homozygous recessive individuals (aa). The phenotype of albinism is represented by a deficiency of skin and hair pogment melanin resulting in white hair and skin. In this population, 35 of the deer are albino and 7.5% of the 135 are heterozygous. What are the expected genetyope frequencies if the population is not evolving? Show workd for full credit. What is the chi squared statistic?

OneClass: There is a population of 135 deer. Some of the deer in the population are albino which is a...

1. A person is described as a carrier for a particular genetic disease. What does this tell you about their genotype?

2. For any given gene, the principle of independent segregation predicts that each gamete produced as a result of meiosis will contain ____________________

3. A pair of alleles is said to be heterozygous when:

4. In a diploid species, cells can have up to ___ alleles of a particular gene.

5. In a cross between a homozygous dominant parent and a homozygous recessive parent, the number of phenotypic classes observed in the offspring is ______

6. For a person of genotype Xx, the genotype of their gametes may be ______________

7. In a "test cross", an individual of unknown genotype is crossed with a ___ individual to determine the unknown genotype.

8. An albino woman has a child with a phenotypically normal man with no family history of albinism (which is a rare recessive disorder). What percentage of their children are likely to be albino?

9. An individual with the dominant phenotype, but an unknown genotype, is test-crossed, and all of the offspring exhibit the dominant phenotype. The genotype of the unknown individual is ______________

10. If two heterozygous individuals for a recessive disease (carriers) have a child, what is the chance that their child will develop the disease?

11. In a monohybrid cross between two true-breeding parents that both exhibit the dominant phenotype, ___ percent of the offspring will exhibit the recessive phenotype.

12. In a particular type of tomato plant, red fruit is dominant over yellow fruit, and dwarf height is a recessive trait. If two heterozygous plants were crossed, what proportion of the offspring would show the dominant phenotype?

13. In a cross between a BbRr individual and a BBRR one, what do the following represent: BR, Br, bR, br?

14. In humans, the gene that determines whether an embryo develops as a male or a female is carried on _____________

amaranthhare726

Kermode bears are white bears that are found in the rainforest on Princess Royal and Gribbell islands along the coast of British Columbia. This subspecies of black bears is known as the Spirit Bear. Its white fur is the result of a single nucleotide replacement in the melanocortin-1 (Mc1r) receptor portion of the gene that leads to the production of adenine instead of guanine. The white fur allele (W) is a recessive allele unique to this subspecies. Dr. Kermit Ritland and his colleagues found that approximately out of a total population of 73 bears on Princess Royal and Gribbell Islands 48 were white (WW). Of the black bears (BB and BW), 12 were homozygous and 13 were heterozygous. The percentage of white bears on the mainland drops off drastically with distance from those islands.

Assuming complete dominance, estimate the observed allele frequencies (maintain 3 significant digits for all calculations) (1pt)?
q =
p =
Thus, for a randomly mating population at equilibrium, the Hardy-Weinberg theorem gives us the genotype frequencies expected for Kermode bears (1pt).
The expected frequency of BB genotypes =
The expected frequency of BW genotypes =
The expected frequency of WW genotypes =
If there is a population of 37 bears on Princess Royal Island, how many would you expect to be black (1pt)?
How many would you expect to be white (1pt)?

You can use the Chi-square statistic to test whether the observed numbers of your BB,
BW, and WW genotypes (your categories) differ from your expected proportions morethan you would expect due to chance. The Chi-square statistic is a probability distributionthat we can use to estimate the probability (âp-valueâ) of finding differences in observedand expected values. If the observed values are very different from the expected values(resulting in a large Chi-square value), we would say there is a low probability (p<0.01)of that difference occurring due to chance alone. This outcome would suggest somemechanism of evolution (drift, natural selection, etc.) is pushing allele frequencies out ofHardy-Weinberg equilibrium. Use the Chi-square calculator to test for differences in your observed numbers of the three genotypes and the expected frequencies on Princess RoyalIsland (using the âfraction expectedâ option) at:https://graphpad.com/quickcalcs/chisquared1.cfm.

Are the observed numbers and expected frequencies significantly different? What doesthis mean is happening to white bears on Princess Royal Island (2pts)?

pearwasp6

Kermode bears are white bears that are found in the rainforest on Princess Royal and Gribbell islands along the coast of British Columbia. This subspecies of black bears is known as the Spirit Bear. Its white fur is the result of a single nucleotide replacement in the melanocortin-1 (Mc1r) receptor portion of the gene that leads to the production of adenine instead of guanine. The white fur allele (W) is a recessive allele unique to this subspecies. Dr. Kermit Ritland and his colleagues found that approximately out of a total population of 73 bears on Princess Royal and Gribbell Islands 48 were white (WW). Of the black bears (BB and BW), 12 were homozygous and 13 were heterozygous. The percentage of white bears on the mainland drops off drastically with distance from those islands.

Assuming complete dominance, estimate the observed allele frequencies (maintain 3 significant digits for all calculations) (1pt)?
q =
p =
Thus, for a randomly mating population at equilibrium, the Hardy-Weinberg theorem gives us the genotype frequencies expected for Kermode bears (1pt).
The expected frequency of BB genotypes =
The expected frequency of BW genotypes =
The expected frequency of WW genotypes =
If there is a population of 37 bears on Princess Royal Island, how many would you expect to be black (1pt)?
How many would you expect to be white (1pt)?

You can use the Chi-square statistic to test whether the observed numbers of your BB,
BW, and WW genotypes (your categories) differ from your expected proportions morethan you would expect due to chance. The Chi-square statistic is a probability distributionthat we can use to estimate the probability (âp-valueâ) of finding differences in observedand expected values. If the observed values are very different from the expected values(resulting in a large Chi-square value), we would say there is a low probability (p<0.01)of that difference occurring due to chance alone. This outcome would suggest somemechanism of evolution (drift, natural selection, etc.) is pushing allele frequencies out ofHardy-Weinberg equilibrium. Use the Chi-square calculator to test for differences in your observed numbers of the three genotypes and the expected frequencies on Princess RoyalIsland (using the âfraction expectedâ option) at:https://graphpad.com/quickcalcs/chisquared1.cfm.

Are the observed numbers and expected frequencies significantly different? What doesthis mean is happening to white bears on Princess Royal Island (2pts)?

amarantheel615

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