When I entered the equation 1/(x+1)^2 into a derivativecalculator, it told me the derivative should be 1/(x^2 + 2x +1),but I don't think I got that result.
Did I do something wrong with my calculation? I've uploaded animage below.
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A street light is mounted at the top of a 15-ft-tall pole. Aman6 ft tall walks away from the pole with a speed of 5 ft!salonga straight path. How fast is the tip of his shadow movingwhenhe is 40 ft from the pole?The answer is 25/3.I let x be the length of shadow, y be the distance between man andpole.I did 6/15=x/(x y)then i got x=2/3ydx/dt=dy/dt(2/3)Then I got (2/3)5= 10/3What did I do wrong. Please don't just give me the answer. Explainto me what I did wrong
Find the limit. lim x?5+ ln(x^2 ? 25) ?
if I plug in I'm gonna get zero but I don't think this is the anwser so this is what I did: ==> 2x/x^2-25 and then use L'Hopital rule ==> 2/2x plugging 5 we get that the limit is 1/5. I don't think that my answer is correct PLEASE someone help a bortha out. A step by step answer would be greatly appreciated.
f(x)= e-x^2/2
Im at the second derivative where I dont know how it got from F"(x)= e^-x^2/2 * (-1) * (-x) * e^(-x^2/2)
there was a point in the middle where the above equation wasmerged into this: -2e^-x^2/2 + 2x , i understand that but dontunderstand how it came to be the term below
to : e^-x^2/2 (-1+x^2)
thanks