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10 Nov 2019
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For the curve r(t) = 9 sin ti + 4tj + 9 cos tk find the unit tangent vector T(t). Use the formula kappa(t) = to find the curvature.
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Elin Hessel
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21 Apr 2019
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Find the unit tangent vector T (t) at the point corresponding to the given value of the parameter t. r(t) = 2t sin ti + t cos 5tj + tk; t = pi/2
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Find the unit tangent vector T (t) at the point corresponding to the given value of the parameter t. r(t) = 2t sin ti + t cos 5tj + tk; t = pi/2
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Consider the helix r(t) COS( t i -t sin (t)j tk Then the curvature is (t) the unit tangent vector is T t 1 the unit normal vector is j+ 1 and the binormal vector is 1 Your answers are expressions in t k.
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