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13 Nov 2019
Find the Maclaurin series for f(x) = sin(x) by computing: f(x) = sin(x) f(0) = f'(0) = f"(0) f"(0) = f(4)(0) = f' (x) = f"(x) = f'"(x) = f(4)(z) = In general (even derivatives) f(2k)(0) = Write out the sum of the first four nonzero terms in the Maclaurin series: (odd derivatives) f2k+(0) In sigma notation the Maclaurin series for sin() is ã«0 The interval of convergence of the series you found above is (-oo, oo). Find the sum of the series (-1)ã±2k+1 22k+1(2k 1)
Find the Maclaurin series for f(x) = sin(x) by computing: f(x) = sin(x) f(0) = f'(0) = f"(0) f"(0) = f(4)(0) = f' (x) = f"(x) = f'"(x) = f(4)(z) = In general (even derivatives) f(2k)(0) = Write out the sum of the first four nonzero terms in the Maclaurin series: (odd derivatives) f2k+(0) In sigma notation the Maclaurin series for sin() is ã«0 The interval of convergence of the series you found above is (-oo, oo). Find the sum of the series (-1)ã±2k+1 22k+1(2k 1)
Jarrod RobelLv2
13 Nov 2019