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13 Nov 2019
Please NEATLY show the steps on how to get each step in the solution. I am especially confused on how to get the derivative of the tangent function
-/5 points LarCalc11 12.5.030. Find the curvature K of the curve r(t) -3 cos(at)i + sin(t)j 9 (sin (Ï t))2 + (cos (Ï t))2), K = (No Response) Solution or Explanation : r(t) 3 cos(t)i + sin(Tt)j : r'(t) =-3Ï sin(Tt)i + Ï cos(nt)j : lirtt)II = Ï/9 (sin(mt))2 + (cos(mt))2 -3 sin(it)i +cos(t)j : T(t)= 9 sin(t)) cos(t) 12 (t)- (9 (sin(Tt)) 2 3/2 + (cos(Ït) 9sin(t)cos(t) llr()ll TV 9 (sin(rt)) + cos(rt) (9 (sin(Tt))+ (cos(Tt) =
Please NEATLY show the steps on how to get each step in the solution. I am especially confused on how to get the derivative of the tangent function
-/5 points LarCalc11 12.5.030. Find the curvature K of the curve r(t) -3 cos(at)i + sin(t)j 9 (sin (Ï t))2 + (cos (Ï t))2), K = (No Response) Solution or Explanation : r(t) 3 cos(t)i + sin(Tt)j : r'(t) =-3Ï sin(Tt)i + Ï cos(nt)j : lirtt)II = Ï/9 (sin(mt))2 + (cos(mt))2 -3 sin(it)i +cos(t)j : T(t)= 9 sin(t)) cos(t) 12 (t)- (9 (sin(Tt)) 2 3/2 + (cos(Ït) 9sin(t)cos(t) llr()ll TV 9 (sin(rt)) + cos(rt) (9 (sin(Tt))+ (cos(Tt) =
Irving HeathcoteLv2
20 Apr 2019