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Assume that you are working with an Antacid tablet that contains 550mg CaCO3 and 110mg Mg(OH)2. Each tablet weighs 745mg.

Part A step 1. Determine the amount of tablet powder that would need to be weighed to give you 1000mg of CaCO3.

Part A Step 3. How much CaCO3 is in the 20 ml portion?

Part A Step 4. How much EDTA is needed for one titration? Given that each mL of EDTA is equivalent to 5.004 mg of CaCO3.

If the tablets (tablet powder) actually contain both CaCO3 and Mg(OH)2 – How much Mg(OH)2 was weighed in Part A Step 1 along with the CaCO3.

Part B Step1: In each ml of filtrate, how much (mg) of each, CaCO3 and Mg(OH)2, exist?

So how much filtrate would be equal to 120mg of CaCO3 and Mg(OH)2?

Part B Step 3: How much EDTA is needed for one titration? (Remember for the Ca present: each mL of EDTA is equivalent to 5.004 mg of CaCO3 and for the Mg present: each mL of EDTA is equivalent to 2.916 mg of Mg(OH)2.)

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Bunny Greenfelder
Bunny GreenfelderLv2
28 Sep 2019
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