Log in
Chemistry
1
answer
0
watching
81
views

Sorry - I am bad at the diagram tool. This is aCis-3-tert-butyl-1,2-epoxycyclohexane molecule undergoing an acidcatalyzed reaction.

I predicted the following molecule as a product. But, my onlineprogram is telling me that I am wrong.

Can someone tell me where I am going wrong on this? Thanks.

Watch
1
answer
0
watching
81
views

For unlimited access to Homework Help, a Homework+ subscription is required.

Casey Durgan
Casey DurganLv2
3 Feb 2019

Unlock all answers

Get 1 free homework help answer.
Already have an account? Log in
Share
discord banner image
Join us on Discord
Chemistry Study Group
Join now

Related textbook solutions

Basic Chemistry
5 Edition,
Timberlake
ISBN: 9780134138046
Principles of Chemistry Molecular Approach
4th Edition,
Tro
ISBN: 9780134112831
Principles of Chemistry Molecular Approach
3rd Edition, 2014
Tro
ISBN: 9780321971944
Chemistry: Structure and Properties
2nd Edition,
Tro
ISBN: 9780134293936
Chemistry: A Molecular Approach
3rd Edition,
Tro
ISBN: 9780321809247
Chemistry: A Molecular Approach
5th Edition,
Tro
ISBN: 9780134874371
Principles of Chemistry: A Molecular Approach
4th Edition,
Tro
ISBN: 9780134895741
Chemistry: The Central Science
14th Edition, 2017
Brown
ISBN: 9780134414232

Related questions

I'm pretty sure that I synthesized butyl acetate (butyl ester)from 1-butanol, but I need to explain how spectroscopy data couldtell you that. I'll award points to the person who can best answerthe following questions:

"Analyze the H-NMR based on chemical shift, splitting, andintegration to support your conclusion (that it's butyl ester)." Ithink the peaks go O-CH2, H3C-C=O, CH2, CH2, and CH3, but I couldbe wrong. It would help me if you can explain this in a bit ofdetail so I can understand it, since I'm bad with readingspectroscopy data.

Assign the three major absorptions in an IR to correspondingfunctional groups. My best guess is written on the IR, am Icorrect, and why or why not?

I need to synthesize this given only saturated hydrocarbons offour or fewer carbons containing only halides and/or alcohols. Ihave decided to use 3 carbon pieces since the compound is 9 carbonslong and went with.

OH-CH2-CH2-CH3 for the first fragment and oxidize this to analdehyde.

CH3-CH(OH)-CH3 for the second fragment and oxidize this into aketone.

the third segment would need to be three carbons long as welland I came up with Br-CH2-CH2-CH3

I now have the ability to put all these elements for the largercompound in place but that is where I am having trouble. I am notreally sure of how to combine these fragments into a largerchunk...

I know what to do after combining them together but the gettingthere is confusing me. I can use any reagent I wish as long as theydo not directly contribute carbons to the final product.

Can someone help me peice my fragements together or tell me ifI'm way off base and I will go back to square one.

Could someone please help me with this chemistry problem? Thank you!

After performing a titration using 20 mL of unknown weak acid with 0.3830M NaOH, I obtained the following results:

0 mL added NaOH = pH 3.80

Final amount of added NaOH = 8.59 mL = pH 12.20

At Equivalence Point: Volume of NaOH = 4.835 mL; pH = approx 8.40

At the Halfway Point; Volume of NaOH = 2.418 mL: pH = 5.15

Ka = 7.08 x 10^-6

Initial [HA] = 0.0926M (determined by M1V1=M2V2 at the equivalence point)

Molar Mass = 1079.8 g/mol (determined by using original mass 1.9977 g/1.85 x 10^-3 moles

-----------------------------------------------------------------------------------------------------------------------------------------------

Now I am asked the following questions in order to check my results for consistency;

Using your experimental Ka value, the concentration of your unknown acid solution and the concentration of the standardized NaOH solution, CALCULATE the pH of the following points on your titration curve:

1) The beginning of the titration before any any NaOH was added

2) 25% of the way to the equivalence point (25% of 4.835 mL is 1.21 mL)

3) 75% of the way to the equivalence point

4) The equivalence point (remember, this is found using Ka and concentrations of acid and base)

5) 20% of the way to the equivalence point (1.20 x 4.835= 5.80 mL)

I've found some info on the internet that says when in the buffer region, the moles of A- = moles of base added and that moles of HA = original moles of HA - moles of base added. Where I got confused was when the equilibrium expression was written as Ka = [H+] [mols Base Added/Volume] ÷ [mols Acid Left/Volume]. I don't know what volumes to use because I always think it makes more sense to use total volume of acid plus base mL's. But maybe you are supposed to use only the volume of each (acid/base) separately, in which case I think the volume of acid would be 20 mL. Maybe this is a totally wrong way to do it- I don't know! Please Help!!!!

Weekly leaderboard

Home
Homework Help 3,900,000
Chemistry 830,000
Start filling in the gaps now
Log in