Consider the following gas phase equilibrium at 298 K.

N2(g) + 3 H2(g) <-> 2 NH3(g)

(a) From standard free energies of formation, calculate theequilibrium constant K at 298 K. (See the appendix:http://www.webassign.net/ebooks/wertzq/html/resource/thermo_prop.html)

(b) Calculate ?G when a reaction mixture consists of 10 atm N2, 10atm H2, and 1 atm NH3.

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Casey DurganLv2

28 Sep 2019

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In the previous question, you had to calculate the the standardFree Energy Change (?G^o) in order to solve for theequilibrium constant, K, for the reaction:

N₂(g) + 3H₂(g) ?2NH₃(g)

This is the Free Energy measured under standardconditions, when the reaction is started with 1.0 M ofeach of the three gases present. Calculate thenon-standard Free Energy change (?G) at 298 K,given the following non-standard initial partial pressures of thethree gases. Answer in kJ.
?G_f^o = -16.6 kJ/mol for NH₃ (g) at298 K