where n > m and n corresponds to the principal quantum number of the higher energy orbital the electron i transitioning from and m corresponds to the principal quantum number of the lower energy orbital the electron is transitioning to and the Rydberg constant 1.097 x 102 nm. Their knowledge helped form the current accepted model of atomic structure. a) The figure to the right shows 434.0 656.3 hydrogen's spectral "signature." Use the Balmer-Rydberg equation to determine the wavelength of the 410.1 486.1 The numbers correspond to the λ emitted by hydrogen in the visible region of the electromagnetic spectrum, in nm drops from a 3s to a 2s orbital in the hydrogen atom and circle that wavelength on the figure. (Be sure to show your work)