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What volume (mL) of 3.0 M NaOH is required to react with 1.7024-g copper(II) nitrate? What mass of copper(II) hydroxide will form?
So far I generated this formula and balanced it: Cu(NO3)2+2NaOH -> Cu(OH)2+2NaNO3
If you could explain the steps, that would be great!
Under a certain set of conditions, the reaction of copper(II) nitrate with sodium hydroxide produces copper(II) hydroxide in 96.5% yield. What mass of copper(II) nitrate would be required to produce 11.4 mg Cu(OH)2 under these conditions?