Calculate xC6H6 (mole fraction) in a benzene-toluene liquid solution that is in equilibriumat 25 degrees celsuis with a vapour phase that contains 62.0 mole % C6H6.Other info:Benzene, 35.8 g, at 25 degrees Celsius has a vapor pressure = 95.1 mmHgToluene, 56.7 g, at 25 degrees Celsius has a vapor pressure = 28.4 mmHgCan someone please explain to me what this is asking, and hopefully explainhow you get to the answer. I don't know what to do with the 62.0 mol% infogiven.

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PLEASE explain steps, having troble solving these two questions

1. a) What are the partial and total pressures of a solution obtained by mixing 35.8 g benzene, C6H6, and 56.7 g toluene, C7H8, at 25.0 degerees Celsius?

b) Determine the composition of the vapor above this benzene-toluene solution. At 25.0 degerees Celsius the vapor pressures of benzene and toluene are 95.1 mm Hg and 28.4 mm Hg respectively.

2. Claculate the mole fraction of benzene in a benzene-toluene solution that is in equilibrium at 25.0 degrees Celsius with a vapor phase that contains 62.0 mol % C6H6. At 25.0 degrees Celsius the vapor pressures of benzene and toluene are 95.1 mm Hg and 28.4 mm Hg respectively.