The energy of H_2^+, lowest M.O. psi = 1 s_A+1 s_B, with internuclear separation R is given by the expression E = E_Hatom - V_1 + V_2/1 + S + e^2/4 pi epsilon_0 R where E_H atom is the energy of an isolated H atom, V_1 is the attractive potential energy between the electron centered on one nucleus and the charge of the other nucleus, V_2 is the attraction between the overlap density and one of the nuclei, S is the overlap integral. The values are given below. Plot (using graph paper, or a plotting program), the second term [-(V_1 + V_2)/(1+S)], the third term [e^2/kR] and Total E. All terms should be in units of E_h(hartrees) and find the approximate bond dissociation energy (in electron volts) and the equilibrium bond length(A). where E_h = 27.3 eV (1 hartree), a_0 = 52.9 pm, and E_Hatom = -1/2 E_n