1. A 10.0 mL sample of vinegar is titrated with 0.100 M NaOH. If it requires 45.00 mL of titrant to reach the endpoint, what is the molarity of acetic acid in the vinegar?

2. (a) If a titration of a different 10.0 mL sample requires 0.00500 moles of base, what mass of acetic acid is in the solution?

2. (b) Assuming the solution has a density of 1.0 g/mL, what is the mass % of acetic acid in the solution?

Question

1. A 10.0 mL sample of vinegar is titrated with 0.100 M NaOH. If it requires 45.00 mL of titrant to reach the endpoint, what is the molarity of acetic acid in the vinegar?

2. (a) If a titration of a different 10.0 mL sample requires 0.00500 moles of base, what mass of acetic acid is in the solution?

2. (b) Assuming the solution has a density of 1.0 g/mL, what is the mass % of acetic acid in the solution?

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