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11 Dec 2019

Solve. PLEASE SHOW STEP-BY-STEP Algebraic method. ln(.280263/1.1)=ΔHvap/8.314 * (1/353 - 1/313) solve for ΔHvap=?

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Casey Durgan
Casey DurganLv2
13 Dec 2019

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Related questions

The vapor pressure of ethanol is 1.00 x 102 mmHg at34.90oC. What is its vapor pressure at 51.73oC? (ΔHvap for ethanol is 39.3 Kj/mol.)

Given the vapor pressure at one temperature, P1, we cancalculate the vapor pressure at a second temperature, P2.

In (P1/P2) = ΔHvap/R (1/T2 - 1/T1)

Where,

ΔHvap for ethanol must have the units of J/mol.

R = 8.314 J/K.mol .. The temperatures must be in Kelvins.

Solve for P2, What is the vapor pressure of ethanol at 51.73oC?

can anyone help me out. I am not sure what I need to do. Please show work, so hopefully I can understand it.


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