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11 Dec 2019
If a water supply has a pH of 8.70, what percentage of the free chlorine is in the form of HOCl on a molar basis?
Hints: For HOCl, pKa = 7.54. (Remember to use units of moles/L with pK values.)
In drinking water, free chlorine is the sum of hypochlorous acid and hypochlorite ion, i.e., free chlorine = [HOCl] + [OClâ] (using units of moles/L). Cl2 is negligible under these conditions.
If a water supply has a pH of 8.70, what percentage of the free chlorine is in the form of HOCl on a molar basis?
Hints: For HOCl, pKa = 7.54. (Remember to use units of moles/L with pK values.)
In drinking water, free chlorine is the sum of hypochlorous acid and hypochlorite ion, i.e., free chlorine = [HOCl] + [OClâ] (using units of moles/L). Cl2 is negligible under these conditions.
Jamar FerryLv2
13 Dec 2019
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