The following readings were made of the diameter of an approximately circular oleic acid film: 12.0, 12.5, 13.0 and 13.2 cm. What is the average diameter and the area of the film?

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Trinidad TremblayLv2

13 Dec 2019

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I am trying to do this problem but am getting a differentanswer. A) I got 0.014 mL(same) B) I got 7x10^-5 (not 6.85 am Idoing something wrong?) C)1100cm^2 (this is where I get lost) Cansome explain these a little better. Thanks

Given Data: average number of drops/mL = 73.0; overall averagediameter of oleic acid film = 38.0 cm. Use this data to calculatefollowing:

a) average volume of oleic acid in film
b) volume of oleic acid per drop of solution
c) average area of oleic acid film
d) height of oleic acid film
e) volume of one oleic acid molecule
f) Avogadro's number
g) Percent disagreement

Formulas to be used:
1) Average volume of one drop of oleic acid solution:
V1 = 1.00 mL / average # of drops
2) Average volume of oleic acid in film in cm^3:
V2 = V1 x (0.0050 mL / 1 mL) x (1 cm^3 / 1 mL)
3) Height of oleic film in cm:
H = V2 in cm^3 / Average area of film in cm^3
* 1 mL = 1 cm^3
4) Volume of one oleic acid molecule in cm^3. A cubic shape isassumed:
V3 = H^3
5) Avogadro's number:
N = (282 g/mol) / (V3 x 0.895 g/cm^3)
6) Percent disagreement:
% dsgmt = [log(6.0225 x 10^23) - log(N)] / log(6.0224 x 10^23) x100

I know how to plug in the values with the equations. However, Ikeep getting a 100%+ disagreement which is unacceptable. I wouldlike some help please. Here are the results that I amgetting:
a) 6.8 x 10^-5 cm^3
b) 1.4 x 10^-2 mL
c) 1134 cm^2
d) 6.04 x 10^-8 cm
e) 2.203 x 10^-22 cm^3
f) 1.43 x 10^24
g) 100%+ error.

Before anyone deletes this question, I am aware that it is not"savvy" to ask more than one question in this question, but thereason I did is that they all relate to one another and cannot besolved without solving the others.

In 1774 Benjamin Franklin described some experiments he had performed on a pond at Clapham Common in London. He observed that a teaspoon (volume 4.5 cm³) of olive oil [Oleic Acid CH₃(CH₂)₇CH=CH(CH₂)₇COOH ; density 0.92 g cm^-3] when spread of a water surface of half an acre (2 x 10³ m²) would calm that entire surface.
Calculate the thickness (in nm) of the surface film and the surface area (in nm²) occupied by an oleic acid molecule on water. Account briefly for your answers.