K p = 0.0198 at 721 K for the reaction 2HI (g) H2 (g) + I2 (g) In a particular experiment, the partial pressures of H2 and I2 at equilibrium are 0.810 and 0.710 atm, respectively. The partial pressure of HI is ________ atm.

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Reid WolffLv2

13 Dec 2019

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At 964 oC the equilibrium constant for the reaction:
2 HI(g) H2(g) + I2(g) is KP = 8.47e-10. If the initial pressure ofHI is 2.92e-03 atm, calculate the equilibrium partial pressures ofHI, H2, and I2. Pick the choice which gives the correct value forthe equilibrium partial pressure of one of these gases.

a) PH2(eq) = 2.13e-08 atm
b) PH2(eq) = 2.55e-07 atm
c) PI2(eq) = 2.55e-07 atm
d) PI2(eq) = 8.50e-08 atm
e) PHI(eq) = 1.70e-07 atm