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12 Dec 2019
chosse the correct answer (show your work)
A-Using the following data reactions:
ÎH° (kJ) H2(g) + Br2(g) â 2HBr(g) -103 H2(g) â 2H(g) 432 Br2(g) â 2Br(g) 193
calculate the energy of an H-Br bond.
522 kJ
52 kJ
261 kJ
728 kJ
364 kJ
B-Given the following information:
Li(s) â Li(g) enthalpy of sublimation of Li(s) = 166 kJ/mol HF(g) â H(g) + F(g) bond energy of HF = 565 kJ/mol Li(g) â Li+(g) + eâ ionization energy of Li(g) = 520. kJ/mol F(g) + eâ â Fâ(g) electron affinity of F(g) = -328 kJ/mol Li+(g) + Fâ(g) â LiF(s) lattice energy of LiF(s) = -1047 kJ/mol H2(g) â 2H(g) bond energy of H2 = 432 kJ/mol
Calculate the change in enthalpy for:
2Li(s) + 2HF(g) â H2(g) + 2LiF(s)
184 kJ
-1064 kJ
-556 kJ
-680 kJ
None of these choices are correct.
chosse the correct answer (show your work)
A-Using the following data reactions:
ÎH° (kJ) | |
H2(g) + Br2(g) â 2HBr(g) | -103 |
H2(g) â 2H(g) | 432 |
Br2(g) â 2Br(g) | 193 |
calculate the energy of an H-Br bond.
522 kJ
52 kJ
261 kJ
728 kJ
364 kJ
B-Given the following information:
Li(s) â Li(g) | enthalpy of sublimation of Li(s) = 166 kJ/mol | |
HF(g) â H(g) + F(g) | bond energy of HF = 565 kJ/mol | |
Li(g) â Li+(g) + eâ | ionization energy of Li(g) = 520. kJ/mol | |
F(g) + eâ â Fâ(g) | electron affinity of F(g) = -328 kJ/mol | |
Li+(g) + Fâ(g) â LiF(s) | lattice energy of LiF(s) = -1047 kJ/mol | |
H2(g) â 2H(g) | bond energy of H2 = 432 kJ/mol |
Calculate the change in enthalpy for:
2Li(s) + 2HF(g) â H2(g) + 2LiF(s)
184 kJ
-1064 kJ
-556 kJ
-680 kJ
None of these choices are correct.
syedazmath1627Lv10
5 Feb 2023
Patrina SchowalterLv2
13 Dec 2019
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