1
answer
0
watching
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views
13 Dec 2019
My question is, is this reaction a order 1 reaction? and if so, is the rate law rate=k[HCI]^1[na2s203]^1
Data Table 2: Varying the Concentration of 0.3 M Na2S2O3
---- C o n c e n t r a t i o n s ---
#
drops
#
drops
# drops
Initial
Initial
Final
Final
Reaction Time (sec)
Reaction
Well
#
HCl
water
Na2S2O3
HCl
Na2S2O3
HCl
Na2S2O3
Trial 1
Trial 2
Average
Rate (sec-1)
1
8
0
12
1M
0.3M
0.4M
0.12M
21.88
21.47
21.67
.046
2
8
6
6
1M
0.15
0.7M
0.11M
46.13
41.72
43.92
.022
3
8
8
4
1M
0.1
0.8M
0.08M
85.91
74.09
80
.016
My question is, is this reaction a order 1 reaction? and if so, is the rate law rate=k[HCI]^1[na2s203]^1 Data Table 2: Varying the Concentration of 0.3 M Na2S2O3 | |||||||||||
---- C o n c e n t r a t i o n s --- | |||||||||||
# drops | # drops | # drops | Initial | Initial | Final | Final | Reaction Time (sec) | Reaction | |||
Well # | HCl | water | Na2S2O3 | HCl | Na2S2O3 | HCl | Na2S2O3 | Trial 1 | Trial 2 | Average | Rate (sec-1) |
1 | 8 | 0 | 12 | 1M | 0.3M | 0.4M | 0.12M | 21.88 | 21.47 | 21.67 | .046 |
2 | 8 | 6 | 6 | 1M | 0.15 | 0.7M | 0.11M | 46.13 | 41.72 | 43.92 | .022 |
3 | 8 | 8 | 4 | 1M | 0.1 | 0.8M | 0.08M | 85.91 | 74.09 | 80 | .016 |
Hubert KochLv2
17 Dec 2019