The pKa of acetic acid, C2H3O2, is 4.75. What is the pH of a buffer in which [HC2H3O2] = 0.20 M and [NaC2H3O2] = 2.0 M? Use the equation: pH=pKa + log([A-] / [HA])

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chocolatefly156Lv1

28 Nov 2020

The pKa of acetic acid, C₂H₃O₂, is 4.75. What is the pH of a buffer in which [HC₂H₃O₂] = 0.20 M and [NaC₂H₃O₂] = 2.0 M?

Use the equation: pH=pKa + log([A-] / [HA])

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Bryllant BaluyutLv10

27 Jan 2021

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You want to make 150 mL of 0.20 M acetic buffer with pH= 4.5. You are given a stock of 1.0 M acetic acid and a bottle of solid sodium acetate salt (MW= 82 g/mol). The formula for this dissociation of acetic acid is shown here.

CH3COOH <----> CH3COO- + H pKa= 4.75

1. What is the ratio of [A]/ [HA] when your buffer pH = 4.75?

2. Determine the concentrations of weak acid and conjugate base in the buffer.

3. How many mL of 1.0 M acetic acid will you need?

A 1.0 L buffer solution contains 0.187 M HC2H3O2 and 0.187 M NaC2H3O2. The value of Ka for HC2H3O2 is 1.8Ã10â5. Because the initial amounts of acid and conjugate base are equal, the pH of the buffer is equal to pKa=âlog(1.8Ã10â5)=4.74. Part A Calculate the new pH after adding 0.019 mol of solid NaOH to the buffer.

how would you prepare a HC2H3O2/C2H3O2- buffer of pH 4.75 starting with 50ml of 0.1 M HC2H3O2 and 50 ml of 0.1 M NAOH