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29 Nov 2019

A generator is to be connected in series with an inductor of L = 2.00 mH and a capacitance C. You are to produce C by using capacitors of capacitances C1 = 4.00microF and C2 = 6.00 microF, either singly or together. What resonant frequencies can the circuit have, depending on the value of C?

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Trinidad Tremblay
Trinidad TremblayLv2
17 Dec 2019
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Related textbook solutions

Physics: Principles with Applications
7th Edition, 2013
Giancoli
ISBN: 9780321625922

Related questions

In the figure below, a generator with an adjustable frequency ofoscillation is connected to resistance R = 350 , inductances L1 =1.00 mH and L2 = 3.00 mH, and capacitances C1 = 100.00 µF, C2 =62.50 µF, and C3 = 87.50 µF.
(a) What is the resonant frequency of the circuit? (Hint: SeeProblem 45 in Chapter 30.)
1 Hz

What happens to the resonant frequency in each situation?
(b) R is increased
2

(c) L1 is increased
3

(d) C3 is removed from the circuit
4

* Read the eBook
*
o Section 31.9 The Series RLC Circuit

A circuit is constructed with two capacitors and an inductor as shown. The values for the capacitors are: C1 = 520 uF and C2 = 84 uF. The inductance is L = 283 mH. At time t =0, the current through the inductor has its maximum value IL(0) = 125 mA and it has the direction shown.

2

1) What is wo, the resonant frequency of this circuit?

2) What is Q1(t1), the charge on the capacitor C1 at time t = t1 = 16.6 ms? The sign of Q1 is defined to be the sameas the sign of the potential difference Vab = Va - Vb at time t = t1.

3) What is Vbc(t1)= Vb - Vc, the voltage across the inductor at time t1 = 16.6 ms? Note that this voltage is a signed number.

 

An inductor ( L= 400 mH), a capacitor (C=5.30μF), a resistor(R=500Ω) are connected in series. A 50.0 Hz AC generator connectedin series to these elements produces a maximum current of 300 mA inthe circuit.

a) What is the impedance of the circuit?

b) What is the phase angle by which the current leads or lagsthe applied voltage?

c) What is the maximum voltage produced by the generator?

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