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11 Dec 2019

m = 350kg
angle = 50 degrees
initial velocity = 150 m/s
Find following:
a) what is velocity after 10 seconds.
b). what is direction of velocity at 10 seconds
c). what is position of rocket at 10 seconds

accleration in x direction is given by = 14.29 * cos (theta) -0.0001286*(v^2)*cos(theta)
accleration in y direction is given by = 14.29 * sin(theta) -0.0001286*(v^2)*sin(theta) - g

You may have to integrate or take derivatives to get theanswer.

Please help urgently!!!!

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12 Dec 2019
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Related textbook solutions

Physics: Principles with Applications
7th Edition, 2013
Giancoli
ISBN: 9780321625922

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Question Two

A rocket is fired at an angle from the top of a tower of height ho = 50.0 m. Because of the design of the engines, its position coordinates are of the form

x(t) = A + Bt2 and y(t) = C + Dt3

where A, B, C, and D, are constants.

Furthermore, the acceleration of the rocket 1.00 s after firing is a = (4.00i + 3.00j) m/s .

Take the origin of coordinates to be at the base of the tower.

(a) Find the constants A, B, C, and D, including their SI units.

(b) At the instant after the rocket is fired, what are its acceleration vector and its velocity?

(c) What are the x- and y-components of the rocket's velocity 10.0 s after it is fired, and how fast is it moving?

(d) What is the position vector of the rocket 10.0 s after it is fired?

 

Question Four

 

Figure 2

A bowling ball weighing 71.2 N is attached to the ceiling by a 3.80-m rope. The ball is pulled to one side and released; it then swings back and forth as a pendulum. As the rope swings through the vertical, the speed of the bowling ball is 4.20 m/s.

(a) What is the acceleration of the bowling ball, in magnitude and direction, at this instant?

(b) What is the tension in the rope at this instant? (10 marks)

A string of mass .03 kg and length 2 m is fixed at one end, anddriven with an oscillator at the other end. The oscillator inducestraveling waves on the string of the form
y=A sin (kx-(omega)t) which traveled down the string, hit the fixedend, and get reflected back as a wave with the form y=Asin(kx+(omega)t).
I'm asked to find the a.) velocity of the waves, b.)frequencyrequired to generate a wave with 4 nodes, and c.) derive a generalequation for standing waves on a string using the two aboveequations.

So I have: m = 0.03 kg and L = 2 m
a.) I have a lot of equations, such as
(lambda) = 2L = 4 m
k = 2(pi)/(lambda) = (pi)/2
µ = m/L = 0.015 kg/m
,but all the equations I know to find velocity involve eithertension or frequency or another variable that I don't have. How doI find the velocity with what I'm given?

b.) I think that 4 nodes is the 2nd harmonic frequency (?) wheren=2 in the equation
f = n * (v/2L). Is this right? If so, I can easily find it when Ihave the answer for velocity.

c.) I think that for this part, I just add the two equationstogether. I'd call one y1 and the other y2. y1 + y2 = generalequation?
[sin a + sin ß = 2 sin ((a+ß)/2) cos ((a-ß)/2)]

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