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12 Dec 2019

Given the reaction:

HCl + NaOH -> H2O + NaCl

Mass of 2.0 M HCl = 50.0 g

Mass of 2.0 M NaOH = 50.0g

Temperature of HCl before mixing = 24 celsius

Temperature of NaOH before mixing = 24 celsius

Temperature after mixing both = 37 celsius

Q solution = 2719.6 J

Q calorimeter = 679.9 J

Total heat of neutralization = -3399.5 J

Moles of acid reacted = 0.1 mole

Moles of water produced = 0.1 mole

Calculate the heat of neutralization per one mole of water formed = ____________ kJ/mole

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Bunny Greenfelder
Bunny GreenfelderLv2
13 Dec 2019
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