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A particle has a charge of +1.9 µC and moves from point A to point B, a distance of 0.28 m. The particle experiences a constant electric force, and its motion is along the line of action of the force. The difference between the particle's electric potential energy at A and B is EPEA - EPEB = +13 x 10-4 J.
(a) Find the magnitude of the electric force that acts on the particle.
(b) Find the magnitude of the electric field that the particle experiences.
A particle has a charge of +1.9 µC and moves from point A to point B, a distance of 0.28 m. The particle experiences a constant electric force, and its motion is along the line of action of the force. The difference between the particle's electric potential energy at A and B is EPEA - EPEB = +13 x 10-4 J.
(a) Find the magnitude of the electric force that acts on the particle.
(b) Find the magnitude of the electric field that the particle experiences.
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Shelley Sundae NaparotaLv10
27 Mar 2019
19 Jan 2021
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