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19 Nov 2019
A force Fx acts on a particle that has a mass of 2 kg. The force isrelated to the position x of the particle by the formula Fx = Cx3,where C = 0.5 if x is in meters and Fx is in Newtons.
(a)What are the SI units of C? (Use the following as necessary: Nand m.)
(b) Find the work W done by this force as the particle moves from x= 3.6 m to x = 1.1 m.
W = J
(c) At x= 1.1 m the force points opposite the direction of theparticle's velocity (speed is 12 m/s). What is its speed at 3.6m?
v3.6m = m/s
Can you tell its direction of motion at x = 3.6 m using only thework-kinetic energy theorem?
yes
no
explain.
A force Fx acts on a particle that has a mass of 2 kg. The force isrelated to the position x of the particle by the formula Fx = Cx3,where C = 0.5 if x is in meters and Fx is in Newtons.
(a)What are the SI units of C? (Use the following as necessary: Nand m.)
(b) Find the work W done by this force as the particle moves from x= 3.6 m to x = 1.1 m.
W = J
(c) At x= 1.1 m the force points opposite the direction of theparticle's velocity (speed is 12 m/s). What is its speed at 3.6m?
v3.6m = m/s
Can you tell its direction of motion at x = 3.6 m using only thework-kinetic energy theorem?
yes
no
explain.
Bunny GreenfelderLv2
5 Mar 2019
