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27 Nov 2019
This is the problem that I was given and I have redone it atleast 5 times already. Can anyone tell me what I am doingwrong?
"A physics professor is pushed up a ramp inclined upward at anangle 28.0 above the horizontal as he sits in his desk chair thatslides on frictionless rollers. The combined mass of the professorand chair is 83.0 kg. He is pushed a distance 2.10 m along theincline by a group of students who together exert a constanthorizontal force of 595 N. The professor's speed at the bottom ofthe ramp is 1.65 m/s. Use the work-energy theorem to find his speedat the top of the ramp."
W=595(2.1)-83(2.1)(9.8)sin(28)=447.577
K1=1/2mv2=[83(1.652)]/2=112.98
so...
v=â[2(447.58+112.98)]/2)=3.68 m/s
This is the problem that I was given and I have redone it atleast 5 times already. Can anyone tell me what I am doingwrong?
"A physics professor is pushed up a ramp inclined upward at anangle 28.0 above the horizontal as he sits in his desk chair thatslides on frictionless rollers. The combined mass of the professorand chair is 83.0 kg. He is pushed a distance 2.10 m along theincline by a group of students who together exert a constanthorizontal force of 595 N. The professor's speed at the bottom ofthe ramp is 1.65 m/s. Use the work-energy theorem to find his speedat the top of the ramp."
W=595(2.1)-83(2.1)(9.8)sin(28)=447.577
K1=1/2mv2=[83(1.652)]/2=112.98
so...
v=â[2(447.58+112.98)]/2)=3.68 m/s
Jarrod RobelLv2
14 Mar 2019
