1
answer
0
watching
153
views
11 Dec 2019
a proton with an initial speed of 800,000 m/s is brought to rest by an electric field.
Part A- Did the proton move into a region of higher potential or lower potential?
Part B - What was the potential difference that stopped the proton?
ΔU = ________V
Part C - What was the initial kinetic energy of the proton, in electron volts?
Ki =_________eV
a proton with an initial speed of 800,000 m/s is brought to rest by an electric field.
Part A- Did the proton move into a region of higher potential or lower potential?
Part B - What was the potential difference that stopped the proton?
ΔU = ________V
Part C - What was the initial kinetic energy of the proton, in electron volts?
Ki =_________eV
VikasLv10
29 Sep 2020