CHEM101 Study Guide - Midterm Guide: Boron, Magnetic Quantum Number, Atomic Orbital

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23 Oct 2018
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CHEM101 Full Course Notes
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CHEM101 Full Course Notes
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Please note that answers written in pencil and using white-out are not eligible for re-grading (cid:1) write answers in the spaces provided (cid:1) only answers written on the front side of the page will be marked. Please note that whenever you do your calculations, make sure to: show your steps one at a time (i. e. showing how the calculation was done, give the correct significant figures, give a suitable unit for the answer. Naturally occurring chlorine is composed of two isotopes: 35cl which has an atomic mass of 34. 969 amu and 37cl which has an atomic mass of 36. 966 amu. If the atomic mass of chlorine is 35. 453 amu, calculate the natural abundance of each isotope. Let the natural abundance of 35cl be x. Therefore, the natural abundance of 37cl = 1 x. Percentage of 37cl = 100 - 75. 76% = 24. 24% b) suggest a reason why atomic masses of elements are seldom in whole numbers.