ECON 1530 Midterm: ECON 1530 Midterm 2015
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ECON 1530 Full Course Notes
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The minimum maximum value of function can be found by first finding the first derivative and equating it to zero. Then we get values of x , for which first derivative is zero, Now we can put these values in the function to check the possible minimum and maximum values. The minimum point of can be found by differentiating the function with respect to x, and then finding the critical point. equating the f (x) to zero we get, , so we get, x = 0, at which we get the minimum value. So now equation of line passing through the points, (0,-9) and (2,0) simplifying, can also be written as, is the equation of the required line: the final answer is, The key here is to express as , its series. The higher order terms here are more than the the degree denominator, and become zero, as we put h=0 of.
