I need help with pre lab 3 and 4 please :)

Experiment 8: Determination of k 45 Exp 8: Determination of Logkow Values for Four Drugs Objectives . Discover how compound polarity affects absorptiorn e Perform extractions Calculate and compare partition coefficients (Olog Kp)of four different pharmaceutical Intreduction Pharmaceutical drug design involves creating a molecule that will target a general region or site and have a therapeutic effect on the patient. Such properties depend on the drug's structure as well as its affinity for different phases in the body. When orally ingested, a drug moves from the stomach into the small intestine. From there, a drug must pass through a layer of cells before it can enter the bloodstrcam (this process is called absorption) and be distributed throughout the body. This requires crossing through largely non-polar cell membrane twice, first to enter the cell from the intestine side and then to exit the cell for entry into the bloodstream Solubility properties have a large influence on the drug's ability to navigate this trek. The drug must be polar enough to convey water solubility so that it does not precipitate out in the water solution that is well, us. For it to be absorbed into the bloodstream, however, a drug mast be non-polar enough to pass through a non-polar lipid bilayer that forms the membranes of cells. A lipid is an organic molecule that can be extracted from living tissues using non-polar organic solvents. A lipid bilayer is a thin membrane made of two lipid layers; the bilayer forms a spherical non-polar barrier separating the inside of a cell from the outside of a cell. The types of lipids that are found in cell membeanes (most commonly phospholipids (Figure 1)) are amphiphilic molecules consisting of hydrophobic ("water-fearing") and hydrophilic ("water-loving") parts. In lipid bilayers, these amphiphilic molecules arrange themselves such that the inside of the bilayer is hydrophobic while the outside (which faces the aqucous intracellular and extracellular environments) is hydrophilic (Figure 2) Figure 1: A phospholipid containing a hydrophilic head and two hydrophobic tails Figure 2: A cartoon representation ofa layer of cells separating the intestne from the bloodstream. An orally-ingested drug must pass through a cell to enter the Noodstream, cncountering both hydrophobic and hydrophilic environments in the process. Diffusion of Drug

I need help with the pre lab questions:)

Experiment 8: Determination of k 45 Exp 8: Determination of Logkow Values for Four Drugs Objectives . Discover how compound polarity affects absorptiorn e Perform extractions Calculate and compare partition coefficients (Olog Kp)of four different pharmaceutical Intreduction Pharmaceutical drug design involves creating a molecule that will target a general region or site and have a therapeutic effect on the patient. Such properties depend on the drug's structure as well as its affinity for different phases in the body. When orally ingested, a drug moves from the stomach into the small intestine. From there, a drug must pass through a layer of cells before it can enter the bloodstrcam (this process is called absorption) and be distributed throughout the body. This requires crossing through largely non-polar cell membrane twice, first to enter the cell from the intestine side and then to exit the cell for entry into the bloodstream Solubility properties have a large influence on the drug's ability to navigate this trek. The drug must be polar enough to convey water solubility so that it does not precipitate out in the water solution that is well, us. For it to be absorbed into the bloodstream, however, a drug mast be non-polar enough to pass through a non-polar lipid bilayer that forms the membranes of cells. A lipid is an organic molecule that can be extracted from living tissues using non-polar organic solvents. A lipid bilayer is a thin membrane made of two lipid layers; the bilayer forms a spherical non-polar barrier separating the inside of a cell from the outside of a cell. The types of lipids that are found in cell membeanes (most commonly phospholipids (Figure 1)) are amphiphilic molecules consisting of hydrophobic ("water-fearing") and hydrophilic ("water-loving") parts. In lipid bilayers, these amphiphilic molecules arrange themselves such that the inside of the bilayer is hydrophobic while the outside (which faces the aqucous intracellular and extracellular environments) is hydrophilic (Figure 2) Figure 1: A phospholipid containing a hydrophilic head and two hydrophobic tails Figure 2: A cartoon representation ofa layer of cells separating the intestne from the bloodstream. An orally-ingested drug must pass through a cell to enter the Noodstream, cncountering both hydrophobic and hydrophilic environments in the process. Diffusion of Drug

The following table presents the solubilities of several gases in water at 25 °C under a total pressure of gas and water vapor of 1 atm. (a) What volume of CH₄(g) under standard conditions of temperature and pressure is contained in 4.0 L of a saturated solution at 25 °C? (b) Explain the variation in solubility among the hydrocarbons listed (the first three compounds), based on their molecular structures and intermolecular forces. (c) Compare the solubilities of O₂, N₂, and NO, and account for the variations based on molecular structures and intermolecular forces. (d) Account for the much larger values observed for H₂S and SO₂ as compared with the other gases listed. (e) Find several pairs of substances with the same or nearly the same molecular masses (for example, C₂H₄ and N₂), and use intermolecular interactions to explain the differences in their solubilities.

The corresponding volume is

b) All three molecules are nonpolar and form very weak interactions with the water molecules. The solubility of ethane is higher that the solubility of methane as ethane is more massive molecule and forms stronger dispersion forces with the water molecule. Ethene is the most soluble gas as the C atoms in ethene are planar, sp² hybridized, and there are π electrons in the orbitals perpendicular to the carbon atoms. π electrons are less tightly held by the nucleus than σ electrons, allowing the dipole of water molecule to disturb the electron density more easily, leading to stronger dipole-induced dipole interactions.

c) The molecular weight is similar for three gases. O₂ and N₂ are nonpolar gases, but more water molecules surround O₂ as it is larger molecule. The O–O bond (double bond) is longer than N–N bond (triple bond). The water attracts nonpolar gases through the weak dipole-induced dipole interactions. NO is the most soluble gas as it has polar bond and the overall molecule is polar as it is linear structure. Water dissolves it via stronger dipole-dipole interactions.

d) H₂S is capable to form weak hydrogen bonds with the water molecules, and these interactions are much stronger than dipole-dipole and dispersion forces. SO₂ is even more soluble in water as it reacts with the water forming H₂SO₃. The very high values for the solubility of gas are the sign that the gas chemically reacts with the solvent.

d) N₂ and CH₄. Solubility of N₂ is lower as N₂ is smaller molecule than CH₄ and less hydrated.

NO and C₂H₆ have similar water solubility. NO is more soluble than ethane and form dipole-dipole interactions, but the dispersion forces of ethane and water are stronger than dispersion forces between NO and water as ethane is larger, more polarizable molecule. The sum of all intermolecular interactions is similar for these two gases, leading to the similar water solubility.

NO and O₂. NO is more soluble as it is polar molecule and form stronger intermolecular forces with polar solvent molecules compared to nonpolar O₂ molecule.

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