CHM ENG 142 Study Guide - Midterm Guide: Uncompetitive Inhibitor, Enzyme Kinetics, Competitive Inhibition

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Due: wednesday, march 4, 2020: enzyme kinetics, the rate of this reaction is r = a[s] / (b + [s]) for constants a and b. Use pssh to solve for a and b as a function of rate constants and the total enzyme concentration [e] t . Pssh on e s: k 1 [e][s] = (k -1 + k 2 )[e s] [e s] = k 1 /(k -1 + k 2 ) [e][s] Site balance: [e] t = [e] + [e s] = [e] (1 + k 1 /(k -1 + k 2 ) [s]) Therefore [e] = [e] t (k -1 + k 2 )/(k -1 + k 2 + k 1 [s]) Rate = k 2 [e s] = k 1 k 2 /(k -1 + k 2 ) [e][s] = k 1 k 2 [e] t [s] / (k -1 + k 2 + k 1 [s])

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