CHEM-51 Midterm: CHEM 51 Dartmouth 122Exam 3SolutionsSpring 09

37 views5 pages
31 Jan 2019
Department
Course
Professor

Document Summary

Find bases of the following vector spaces and state their. A basis of col(a) is formed by the pivot columns of a, namely. So dim(col(a)) (cid:3) 2. (b) the row space of a. Nonzero rows of rref(a) form a basis of row space, namely (1, 3, 0, 2, 5) and (0, 0, 1, 2, 1). So dim(row(a)) (cid:3) 2. (c) the null space of a. Free variables: x2 (cid:3) t1, x4 (cid:3) t2, x5 (cid:3) t3. Ax (cid:3) 0: x1 (cid:3) 3t1 2t2 5t3, x2 (cid:3) t1, x3 (cid:3) 2t2 + t3, x4 (cid:3) t2, x5 (cid:3) t3. General solution in vector form is x (cid:3) t1v1 + t2v2 + t3v3, where v1 (cid:3) These three vectors form a basis of nul(a). So dim(nul(a)) (cid:3) 3. (d) the orthogonal complement of the column space of a. A vector y in r3 is perpendicular to the columns of a if and only if aty (cid:3) 0.

Get access

Grade+
$40 USD/m
Billed monthly
Grade+
Homework Help
Study Guides
Textbook Solutions
Class Notes
Textbook Notes
Booster Class
10 Verified Answers

Related textbook solutions

Related Documents

Related Questions