CHEM-6 Midterm: Chem 6 Dartmouth Spring Exam 1S
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Sample exam 1 solutions: (a) to find the reaction orders, look at the dependence of rate on concentrations. From rows 1 and 3, cutting the [ocl ] in half cuts the rate in half, so the reaction is 1st order in ocl . Similarly, from rows 2 and 3, cutting the [i ] in half cuts the rate in half, so it"s also first order in i . To find the rate constant k, plug in some data. From row 1, for example, rate = 4. 8x10 4ms 1 = k [0. 0040m] [0. 0020m]/[1. 00m] k = 60s 1: note for 2003, 2004, 2005, etc. If you found this one difficult, don"t worry too muchwe have not looked at similar "pressure" problems this year. First define p = total pressure, po = initial pressure of c2h4o, pa = pressure of. C2h4o, pb = pc = pressure of ch4 = pressure of co, and x = number of moles of.
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