MATH 1551 : Test2 Sol
Document Summary
In questions 1 5, nd f (x) for the given function f . You do not need to simplify your answers: f (x) = 2. 1) sec2 x 4x tan x (2x2. 2) 3/2 f (x) = (ln 2) sin x2cos x: f (x) = (ex + 1) sin 1 x. Solution. f (x) = ex sin 1 x + ex + 1. 1 x2: find an equation of the tangent line to the curve y = e2x + cos x at the point (0, 2). We have y = 2e2x of the tangent line is. Sin x, y(0) = 2 and y (0) = 2, so an equation y = 2x + 2: use implicit di erentiation to nd y if x2 + 3y2 = 9. Do simplify your answer as much as possible. We have 2x + 6yy = 0, so y = y xy y = y2.
